y= the square root of (4x+2). Here's what i did so far, before getting stuck: f'= (4x+2)^(1/2) (1/2)(4x+2)^(-1/2) Where do i go from here?
Follow Math Help Forum on Facebook and Google+
You were suppose to use the chain rule. dy/dx = du/du x du/dx So let u = 4x + 2
View Tag Cloud