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**dataspot** The acceleration of a bus is given by $\displaystyle a_{x}(t)= \alpha t$, where $\displaystyle \alpha = 1.27 m/s^3$ is a constant.

If the bus's velocity at time $\displaystyle t_1 = 1.07 s$ is $\displaystyle 5.05 m/s$, what is its velocity at time$\displaystyle t_2 = 2.19 s$?

If the bus's position at time $\displaystyle t_1 = 1.07 s$ is $\displaystyle 5.96 m$, what is its position at time $\displaystyle t_2 = 2.19 s$?

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I tried doing $\displaystyle 5.05m/s + (1.27m/s^3)(2.19s)$, but that can't be right as $\displaystyle (1.27m/s^3)(2.19s)$ is the acceleration of the bus. So I'm not sure how to proceed now.