Thread: [SOLVED] stuck! calculusII

find the area of the curves

y^2 - 4x = 4 and 4x-y=16


i know you can set this one to x = etc.... then u gotta evaluate the graph of the functions differntly kinda.. anyways this problem is giving me tons of trouble

Originally Posted by Legendsn3verdie

find the area of the curves

y^2 - 4x = 4 and 4x-y=16


i know you can set this one to x = etc.... then u gotta evaluate the graph of the functions differntly kinda.. anyways this problem is giving me tons of trouble

I take it you're saying you want to find the area bounded by the curve and the x-axis...

You haven't told us our limits of integration... in other words, between which x values...

Originally Posted by Prove It

I take it you're saying you want to find the area bounded by the curve and the x-axis...

You haven't told us our limits of integration... in other words, between which x values...

i got from -4 to 5

Originally Posted by Legendsn3verdie

i got from -4 to 5

It can't be, because the first function is not defined at .

Originally Posted by Prove It

It can't be, because the first function is not defined at .

88/3 is the wrong answer where did i go wrong?

Quick question is this bounded by the y axis as well? I'm asking becuase you don't have shading to the left of the y axis?

Originally Posted by 11rdc11

Quick question is this bounded by the y axis as well? I'm asking becuase you don't have shading to the left of the y axis?

no its not, but dont waste ur time on it, i got the right answer now, i made a stupid algebra error that threw me off for about 2-3hours! what a waste of time! guys dont waste ur time on this i got it solved, thanks for your concern 11rdc.


edit: if anyone is bored and wants to play around with this one.. the answer is 243/8