# Thread: [SOLVED] stuck! calculusII

1. ## [SOLVED] stuck! calculusII

find the area of the curves

y^2 - 4x = 4 and 4x-y=16

i know you can set this one to x = etc.... then u gotta evaluate the graph of the functions differntly kinda.. anyways this problem is giving me tons of trouble

2. Originally Posted by Legendsn3verdie
find the area of the curves

y^2 - 4x = 4 and 4x-y=16

i know you can set this one to x = etc.... then u gotta evaluate the graph of the functions differntly kinda.. anyways this problem is giving me tons of trouble
I take it you're saying you want to find the area bounded by the curve and the x-axis...

You haven't told us our limits of integration... in other words, between which x values...

3. Originally Posted by Prove It
I take it you're saying you want to find the area bounded by the curve and the x-axis...

You haven't told us our limits of integration... in other words, between which x values...

i got from -4 to 5

4. Originally Posted by Legendsn3verdie
i got from -4 to 5
It can't be, because the first function is not defined at $x=-4$.

5. Originally Posted by Prove It
It can't be, because the first function is not defined at $x=-4$.

6. 88/3 is the wrong answer where did i go wrong?

7. Quick question is this bounded by the y axis as well? I'm asking becuase you don't have shading to the left of the y axis?

8. Originally Posted by 11rdc11
Quick question is this bounded by the y axis as well? I'm asking becuase you don't have shading to the left of the y axis?

no its not, but dont waste ur time on it, i got the right answer now, i made a stupid algebra error that threw me off for about 2-3hours! what a waste of time! guys dont waste ur time on this i got it solved, thanks for your concern 11rdc.

edit: if anyone is bored and wants to play around with this one.. the answer is 243/8