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Math Help - Another calculus problem

  1. #1
    Junior Member
    Joined
    Aug 2008
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    72

    Another calculus problem

    This question has stumped me too,

    I need to find the general solution in implicit form of,

    dy/dx = sqrt (10+y^2) / y

    (x>0, y>o)
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  2. #2
    Super Member
    Joined
    Aug 2008
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    If it's \frac{dy}{dx}=\frac{\sqrt{10+y^2}}{y} then just separate variables and integrate both sides:

    \int \frac{y dy}{\sqrt{10+y^2}}=\int dx

    I get (x+c)^2-y^2=10.
    Last edited by shawsend; September 10th 2008 at 08:36 AM. Reason: grammar
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