1. ## Another calculus problem

This question has stumped me too,

I need to find the general solution in implicit form of,

dy/dx = sqrt (10+y^2) / y

(x>0, y>o)

2. If it's $\frac{dy}{dx}=\frac{\sqrt{10+y^2}}{y}$ then just separate variables and integrate both sides:

$\int \frac{y dy}{\sqrt{10+y^2}}=\int dx$

I get $(x+c)^2-y^2=10$.