Another continuity problem I'm having trouble on On the interval [0,2pi] where is the function f(x) = (sqrt 2cosx - (sqrt 3)) continuous? Thanks again guys Edit : Sorry about that Plato. Forgot to put the X after Cos. Thanks
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That function is meanless as posted. Please review what you have posted and correct the function. There is no x in the agrument.
is this your function?
In either case the function is not even define. Can you have the square root of a negative number?
Well there is an answer for it and it's [0, pi/6] U [11pi/6, 2pi]
I'm assuming that the function is if that is the case, then you know why, correct? simplifying the inequality ... your "answer" is the set of x-values for which the above inequality is true.
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