Another continuity problem I'm having trouble on
On the interval [0,2pi] where is the function f(x) = (sqrt 2cosx - (sqrt 3)) continuous?
Thanks again guys
Edit : Sorry about that Plato. Forgot to put the X after Cos. Thanks
I'm assuming that the function is
$\displaystyle f(x) = \sqrt{2\cos{x} - \sqrt{3}}$
if that is the case, then
$\displaystyle 2\cos{x} - \sqrt{3} \geq 0$
you know why, correct?
simplifying the inequality ...
$\displaystyle \cos{x} \geq \frac{\sqrt{3}}{2}$
your "answer" is the set of x-values for which the above inequality is true.