Another continuity problem I'm having trouble on
On the interval [0,2pi] where is the function f(x) = (sqrt 2cosx - (sqrt 3)) continuous?
Thanks again guys
Edit : Sorry about that Plato. Forgot to put the X after Cos. Thanks
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That function is meanless as posted.
Please review what you have posted and correct the function.
There is no x in the agrument.
is this your function?
In either case the function is not even define.
Can you have the square root of a negative number?
Well there is an answer for it and it's
[0, pi/6] U [11pi/6, 2pi]
I'm assuming that the function is
if that is the case, then
you know why, correct?
simplifying the inequality ...
your "answer" is the set of x-values for which the above inequality is true.
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