Another continuity problem I'm having trouble on

On the interval [0,2pi] where is the function f(x) = (sqrt 2cosx - (sqrt 3)) continuous?

Thanks again guys

Edit : Sorry about that Plato. Forgot to put the X after Cos. Thanks

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- Sep 9th 2008, 04:15 PMAftermeAnother Continuity Problem
Another continuity problem I'm having trouble on

On the interval [0,2pi] where is the function f(x) = (sqrt 2cosx - (sqrt 3)) continuous?

Thanks again guys

Edit : Sorry about that Plato. Forgot to put the X after Cos. Thanks - Sep 9th 2008, 04:21 PMPlato
That function is meanless as posted.

Please review what you have posted and correct the function.

There is no x in the agrument. - Sep 9th 2008, 04:29 PMskeeter
is this your function?

- Sep 9th 2008, 04:41 PMPlato
In either case the function is not even define.

Can you have the square root of a negative number? - Sep 9th 2008, 05:28 PMAfterme
Well there is an answer for it and it's

[0, pi/6] U [11pi/6, 2pi] - Sep 9th 2008, 05:54 PMskeeter
I'm assuming that the function is

if that is the case, then

you know why, correct?

simplifying the inequality ...

your "answer" is the set of x-values for which the above inequality is true.