use l'hospital's rule to find the limit:
1. lim (tan 2x)^x
x-> 0+
i got 1 using ln y, but im not sure if its right..
2. lim (1+ (a/x))^bx
x-> INFINITY
again i got 1...but am unsure
any help is appreciated...thanks!!
Hello,
I get 1 too
Substitute2. lim (1+ (a/x))^bx
x-> INFINITY
Thus and
Remember the rule
Therefore :
(by taking the logarithm and applying l'Hospital's rule)
(a little substitution can be done if t tends to )
Otherwise, applying the logarithm :
Then apply l'Hospital's rule...