# Math Help - Finding limits

1. ## Finding limits

Can someone help me figure out the steps to solving this problem?

limit[(x3-1)/(x2-1),x,1]=

2. Originally Posted by sjenkins
Can someone help me figure out the steps to solving this problem?

limit[(x3-1)/(x2-1),x,1]=
When $x \ne 1$

$\frac{x^3-1}{x^2-1}=\frac{(x-1)(x^2+x+1)}{(x-1)(x+1)}=\frac{x^2+x+1}{x+1}$

Hence:

$\lim_{x \to 1}\frac{x^3-1}{x^2-1}=\frac{1^2+1+1}{1+1}=3/2$

RonL