Can someone help me figure out the steps to solving this problem? limit[(x3-1)/(x2-1),x,1]=
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Originally Posted by sjenkins Can someone help me figure out the steps to solving this problem? limit[(x3-1)/(x2-1),x,1]= When $\displaystyle x \ne 1$ $\displaystyle \frac{x^3-1}{x^2-1}=\frac{(x-1)(x^2+x+1)}{(x-1)(x+1)}=\frac{x^2+x+1}{x+1}$ Hence: $\displaystyle \lim_{x \to 1}\frac{x^3-1}{x^2-1}=\frac{1^2+1+1}{1+1}=3/2$ RonL
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