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Math Help - Finding limits

  1. #1
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    Finding limits

    Can someone help me figure out the steps to solving this problem?

    limit[(x3-1)/(x2-1),x,1]=
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  2. #2
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    Quote Originally Posted by sjenkins View Post
    Can someone help me figure out the steps to solving this problem?

    limit[(x3-1)/(x2-1),x,1]=
    When x \ne 1

    \frac{x^3-1}{x^2-1}=\frac{(x-1)(x^2+x+1)}{(x-1)(x+1)}=\frac{x^2+x+1}{x+1}

    Hence:

    \lim_{x \to 1}\frac{x^3-1}{x^2-1}=\frac{1^2+1+1}{1+1}=3/2

    RonL
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