Hello, Legendsn3verdie!
The graph looks like this:Find the area enclosed by: . andCode:| * | * * * | * | *:::* |*:::::* |:::::::- - - - - *:-:-:-:* - - - - |::::::: |*:::::* | *:::* | * * * * | * |
It is easier integrate "sideways" ... with respect to
We have: .
They intersect when: .
. . They intersect at:
Formula: .
Due to the symmtry of the region, we can integrate from to
. . and double the result.
We have: .
. . . . .
If you are to find the area between and , we see that we have two parabolas , and .
To find where they intersect, set these equations equal to each other:
If graphed correctly, we can see that the area integral should be written in terms of y:
Does this make sense?
If not, try to see how I set up my integral from the graph of these two functions:
--Chris