hey i have im practising some problems and i dont know where to start on this question.
find an equation for the line tangent to the graph of y = secx at (pie/3,2)
any suggestions?
1) Verify that (pi/3,2) is ON the graph. This is a point on the line.
2) Find the derivative of the function, y' = ???
3) Evaluate the derivaive at x = pi/3. This is the slope of the line.
4) Remember your algebra and use the Point-Slope form of a line.