First we have: 8 Ln(e^a) + 9 ln(B^e)
8a Ln(e) + 9 ln(B^e)
8a + 9ln(B^e)
Anybody know what to do from here?
wait, i'm confused. it seems you are working with powers in the second line, yet in the first line you only have products. which is it?
do you mean $\displaystyle 8 \ln (e^A) + 9 \ln (B^e)$ ?
if so, you should indicate powers by using "^" just as you did in the second line
Oh !
I think I can see what you're asked.
use these rules $\displaystyle a \ln b=\ln(b^a)$ and $\displaystyle \ln(a)+\ln(b)=\ln(ab)$ and $\displaystyle (a^b)^c=a^{bc}$
--> $\displaystyle 8 \ln(e^a)=\ln((e^a)^8)=\ln(e^{8a})$
--> $\displaystyle 9 \ln(b^e)=\ln(\dots)$
-----> $\displaystyle 8 \ln(e^a)+9 \ln(b^e)=\ln(\dots)+\ln(\dots)=\ln(\dots \dots)$