evaluate the limit, if it exists:
lim x^2+x-6/x-2
→ 2
How do I go about solving this?
$\displaystyle \mathop {\lim }\limits_{x \to 2} \frac{{x^2 + x - 6}}
{{x - 2}} \hfill \\$
$\displaystyle = \mathop {\lim }\limits_{x \to 2} \frac{{\left( {x + 3} \right)\left( {x - 2} \right)}}
{{x - 2}} \hfill \\$
$\displaystyle = \mathop {\lim }\limits_{x \to 2} \left( {x + 3} \right) \hfill \\$
$\displaystyle = 2 + 3 \hfill \\$
$\displaystyle = 5 \hfill \\ $