Cylindrical shells revolved about the line y=1

**noppawit** · September 7th 2008, 04:50 AM

Use cylindrical shells to find the volume of the solid that is generate when the region that enclosed by $y=x^3$ , $y=1$ , $x=0$ is revolved about the line $y=1$

As it said "cylindrical shells" to find the volume.

I transform $y=x^3$ to $x=\sqrt[3]{y}$

The area of this surface is $2\pi x f(x)$ , and then integrate from a to b to get cylindrical shells formula. For this problem, I changed a to b to c to d. And $2\pi x f(x)$ to $2\pi y f(y)$

My problem is to be revolved about the line y=1, that means it similar to revolve about x-axis, but higher 1 unit. I don't know how to calculate it.

I don't know how to find y and f(y).

Please help, thank you.

**noppawit** · September 7th 2008, 05:08 AM

Am I correct, if the answer is $2\pi$ by using $2\pi (y+1)(1-\sqrt[3]{y})$ as area.

????

**galactus** · September 7th 2008, 05:35 AM

With the y+1, you are revolving about y=-1.

With shells, the cross sections are parallel to the axis about which you are revolving. So, we integrate in terms of x.

$2{\pi}\int_{0}^{1}(1-x)x^{3}dx$

Thread: Cylindrical shells revolved about the line y=1

LinkBack

Thread Tools

Display

Cylindrical shells revolved about the line y=1

Similar Math Help Forum Discussions

Need help with cylindrical shells

Integrals using cylindrical shells when rotated on non-axis line

Cylindrical Shells

Cylindrical shells:

Cylindrical Shells Help

Search Tags