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Math Help - Pls Chk Work (dx/dt)

  1. #1
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    Pls Chk Work (dx/dt)

    Find dx/dt given x = sqrt(1 + cot 3t)?

    dx/dt = 1/2 ( 1+cos3t) ^(-˝) [0 - cosec˛ 3t(3)]

    dx/dt = 1/2{ 1/(1+cost3t)˝ } {-3cosec˛ 3t}

    = [ (-3/2 ) (cosec˛3t) {1/(1+cos3t)˝} ]
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  2. #2
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    \frac{-3csc^{2}(3t)}{2\sqrt{1+cot(3t)}}

    Looks good.
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  3. #3
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    Could you convert the entire solution using the code you used? I am new to posting online and the example would be useful, and easier to read!
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  4. #4
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    Click quote and see what the code is. With a little practice you, too, can learn LaTex. I converted what you had.

    Find \frac{dx}{dt} given x = \sqrt{1 + cot 3t}?

    \frac{dx}{dt} = \frac{1}{2}( 1+cot(3t))^{\frac{-1}{2}}[0 - csc˛(3t)]

    \frac{dx}{dt} = \frac{1}{2}\frac{1}{\sqrt{1+cot(3t)}}{(-3csc˛ (3t))}
    = (\frac{-3}{2}) (csc˛(3t)) {\frac{1}{\sqrt{1+cot(3t)}}

    = \frac{-3csc^{2}(3t)}{2\sqrt{1+cot(3t)}}
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