Find dx/dt given x = sqrt(1 + cot 3t)?

dx/dt = 1/2 ( 1+cos3t) ^(-˝) [0 - cosec˛ 3t(3)]

dx/dt = 1/2{ 1/(1+cost3t)˝ } {-3cosec˛ 3t}

= [ (-3/2 ) (cosec˛3t) {1/(1+cos3t)˝} ]

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- August 7th 2006, 05:52 PMYogi_Bear_79Pls Chk Work (dx/dt)
Find dx/dt given x = sqrt(1 + cot 3t)?

dx/dt = 1/2 ( 1+cos3t) ^(-˝) [0 - cosec˛ 3t(3)]

dx/dt = 1/2{ 1/(1+cost3t)˝ } {-3cosec˛ 3t}

= [ (-3/2 ) (cosec˛3t) {1/(1+cos3t)˝} ] - August 7th 2006, 06:08 PMgalactus

Looks good. :) - August 7th 2006, 06:17 PMYogi_Bear_79
Could you convert the entire solution using the code you used? I am new to posting online and the example would be useful, and easier to read!

- August 7th 2006, 06:46 PMgalactus
Click quote and see what the code is. With a little practice you, too, can learn LaTex. I converted what you had.

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