what i have so far is, leaving the x on the left aside for abit.

then

then

now what do i do with the x? (thats if my calculations are correct)

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- Sep 6th 2008, 02:46 AMjvignaciodifferentiation question!

what i have so far is, leaving the x on the left aside for abit.

then

then

now what do i do with the x? (thats if my calculations are correct) - Sep 6th 2008, 03:01 AMdammitpoo
Product rule:

- Sep 6th 2008, 03:14 AMwoody198403
To continue from what dammitpoo said

the product rule is

where and

So and ............which is what you calculated but you forgot to cancel the 2's.

You should be able to finish it from here....just plug it in to the product rule above.