I did do that is there another step? I seem to be missing omething
for the dot product i get
(10i+j+20k)-(20i+j-10k) which would give me -10i+10k. I know the j coefficient is 0 but where did i go wrong with the others?
I did do that is there another step? I seem to be missing omething
for the dot product i get
(10i+j+20k)-(20i+j-10k) which would give me -10i+10k. I know the j coefficient is 0 but where did i go wrong with the others?
I said cross product, not dot product.
Are you aware there are two different way of multiplying two vectors? Have you been taught how to take the cross product of two vectors?
yes im aware and i did the cross product i don't know why i said dot.
So -10i+10k is perpendicular to a and b. Obviously any scalar multiple of -10i+10k is also perpendicular. So 10i - 10k is perpendicular (and satisfies the requirement of the i-component being positive).
Do you know how to get a unit vector in the direction of 10i - 10k ?