This is the problem I'm having trouble with right now and its racking my brain, any help would be appreciated:
Consider a quadratic function Q(y)=Ay2+By+C. If Q(2)=0, Q(3)=0 and Q(1)=-4, find C the constant term in Q.
for Q(2)=0,
4A + 2B + C =0 .......................................eqn. (1)
for Q(3)=0,
9A + 3B + C = 0 ..................................... eqn.(2)
for Q(1) = - 4,
A + B + C = - 4 .......................................eqn.(3)
subtract eqn(3) from eqn(1) and eqn (2), we get:
3A + B = 4 ............................................EQN(4)
and 8A + 2B =4
or,
4A + B =2 ..........................................EQN(5)
Solve EQN(4) AND EQN(5):
we get:
A = - 2, B = 10
Put these values in eqn(3), we got C = - 12