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Math Help - differention 2

  1. #1
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    differention 2

    differentiate this:

    <br /> <br />
f (x) = xsecx<br /> <br />

    <br /> <br />
f '(x) = (1)(secx) + (x)(tanxsecx)<br />
= secx + xtanxsecx<br /> <br /> <br />


    help pleaseee?
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  2. #2
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    Quote Originally Posted by jvignacio View Post
    differentiate this:

    <br /> <br />
f (x) = xsecx<br /> <br />

    <br /> <br />
f '(x) = (1)(secx) + (x)(tanxsecx)<br />
= secx + xtanxsecx<br /> <br /> <br />


    help pleaseee?
    Yes, you are all right using the product rule.
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  3. #3
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    Quote Originally Posted by Shyam View Post
    Yes, you are all right using the product rule.
    is that the final answer?

    f '(x) = secx + xtanxsecx
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  4. #4
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    Quote Originally Posted by jvignacio View Post
    is that the final answer?

    f '(x) = secx + xtanxsecx
    Yes, it is correct.

    It looks neater written as f'(x) = \sec x \left(1 + x\tan x \right).
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  5. #5
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    Quote Originally Posted by Air View Post
    Yes, it is correct.

    It looks neater written as f'(x) = \sec x \left(1 + x\tan x \right).
    how did u get it in that form?
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  6. #6
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    Quote Originally Posted by jvignacio View Post
    how did u get it in that form?
    You have:

    f'(x) = \sec x + x \sec x \tan x

    There is a common \sec x in the equation so factorise it out.

    f'(x) = \sec{x} \left( 1 + x\tan x \right)

    You still get full marks for writing it in your form but it looks neater to have it factorised.
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  7. #7
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    Quote Originally Posted by Air View Post
    You have:

    f'(x) = \sec x + x \sec x \tan x

    There is a common \sec x in the equation so factorise it out.

    f'(x) = \sec{x} \left( 1 + x\tan x \right)

    You still get full marks for writing it in your form but it looks neater to have it factorised.

    thank you!!!
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