....function is horizontal.
x cubed - 12x + 2
wouldn't that be 0 and 2. by taking the derivative and solving for x, i get only 2, how do i find the other number(s)?
Hi to find a horizontal tangent line to a function you take the derivative and equal it to 0
$\displaystyle f(x) = x^3 -12x+2$
$\displaystyle f'(x) = 3x^2 -12$
$\displaystyle 0= 3x^2 -12$
$\displaystyle x = 2$ and $\displaystyle x = -2$
Shoot to late again lol