....function is horizontal. x cubed - 12x + 2 wouldn't that be 0 and 2. by taking the derivative and solving for x, i get only 2, how do i find the other number(s)?
Follow Math Help Forum on Facebook and Google+
Originally Posted by plstevens ....function is horizontal. x cubed - 12x + 2 wouldn't that be 0 and 2. by taking the derivative and solving for x, i get only 2, how do i find the other number(s)? The derivative is Setting it equal to zero, we get These are the only values where the function has horizontal tangents. Does this make sense? --Chris
Hi to find a horizontal tangent line to a function you take the derivative and equal it to 0 and Shoot to late again lol
thanks
9x^7/5-5x^2+10^4 Now here i worked this out but the computer keep saying my answer of 63/5x^2/5-10x
the computer keep saying its wrong, where did i possibly go wrong on this one
Is this what it looks like?
View Tag Cloud