Show that if , and , then there exist -neighborhoods of and of such that =
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any reason why you divided by 4?
Originally Posted by hockey777 any reason why you divided by 4? Two reasons: it works & I like 4.
Sorry one more question. What else was throwing me off in this problem was the fact I don't think it's clear for a beginner like me. I think the problem suggest that should be the same for both, but I'm not sure. Is that true?
No there is no requirement the neighborhoods have the same radius.
But I gave you a value that will work for both.
Now suppose that .
That is a clear contradiction.
So U & V must have nothing in common.
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