# Integration by Parts again

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• Sep 2nd 2008, 07:49 PM
symstar
[solved]Integration by Parts again
Not quite sure what to pick for u and dv.
$\int_{1}^{2}(\ln{x})^2dx$

I considered $u=\ln{x}$ and $dv=x^{2}dx$ i.e considering it as a function in a function. Can I do this; Should I do this?

Edit: Over-complicating the situation as usual. I found my problem and solved it.