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About LinkBackshow does one go about finding the critical points to this function, given its first and 2nd derivative.
 = \frac{{b + 3}}{{b^2 + 2b}} \\ <br />
f'(b) = \frac{{ - b^2 - 6b - 6}}{{b^2 (b + 2)^2 }} \\ <br />
f''(b) = \frac{{2(b^3 + 9b^2 + 18b + 12)}}{{b^3 (b + 2)^3 }} \\ <br />
\end{array}<br />
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To find all stationary points, set the first derivative equal to zero:Originally Posted by Craka
how does one go about finding the critical points to this function, given its first and 2nd derivative.
This implies that
To find the remaining critical points, look for a value of b that causes the first derivative to be undefined:
In other words, where
This implies that
These two b values are the only critical points.
I hope this helps!
--Chris
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