Why it is "3e^u + c" and not "3(e^u + c)" ?
Thanks...
Hi zorspas,
$\displaystyle C$ is an arbitrary constant. If you had $\displaystyle 3(e^u+C)=3e^u+3C$ the $\displaystyle 3C$ is still constant and so this could be be written $\displaystyle 3e^u+A$ where $\displaystyle A=3C$ is a constant which is the same as $\displaystyle 3e^u+C$ as both $\displaystyle A$ and $\displaystyle C$ are constant. It's just quicker and easier to write.