# substitution rule

• Sep 1st 2008, 03:07 AM
zorspas
substitution rule
• Sep 1st 2008, 03:13 AM
Sean12345
Hi zorspas,

$C$ is an arbitrary constant. If you had $3(e^u+C)=3e^u+3C$ the $3C$ is still constant and so this could be be written $3e^u+A$ where $A=3C$ is a constant which is the same as $3e^u+C$ as both $A$ and $C$ are constant. It's just quicker and easier to write.
• Sep 1st 2008, 03:13 AM
mr fantastic
$3 e^u + C$ is equivalent to $3 (e^u + K)$.

1. Note the different symbol used for each arbitrary constant.
2. C = 3K.
• Sep 3rd 2008, 01:18 AM
zorspas
Thanks a lot...