http://tutorial.math.lamar.edu/Class...s/eq0019MP.gifhttp://tutorial.math.lamar.edu/Class...iles/empty.gifhttp://tutorial.math.lamar.edu/Class...es/eq0019M.gif

Why it is "3e^u + c" and not "3(e^u + c)" ?

Thanks...

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- Sep 1st 2008, 03:07 AMzorspassubstitution rule
http://tutorial.math.lamar.edu/Class...s/eq0019MP.gifhttp://tutorial.math.lamar.edu/Class...iles/empty.gifhttp://tutorial.math.lamar.edu/Class...es/eq0019M.gif

Why it is "3e^u + c" and not "3(e^u + c)" ?

Thanks...

- Sep 1st 2008, 03:13 AMSean12345
Hi zorspas,

$\displaystyle C$ is an arbitrary constant. If you had $\displaystyle 3(e^u+C)=3e^u+3C$ the $\displaystyle 3C$ is still constant and so this could be be written $\displaystyle 3e^u+A$ where $\displaystyle A=3C$ is a constant which is the same as $\displaystyle 3e^u+C$ as both $\displaystyle A$ and $\displaystyle C$ are constant. It's just quicker and easier to write. - Sep 1st 2008, 03:13 AMmr fantastic
- Sep 3rd 2008, 01:18 AMzorspas
Thanks a lot...