This is a problem I am having trouble with: This is the formula we were taught in class to use for these types of problems: I came up with this but I am sure it's wrong.
Last edited by redman223; Aug 31st 2008 at 02:35 PM.
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Originally Posted by redman223 This is a problem I am having trouble with: This is the formula we were taught in class to use for these types of problems: I came up with this but I am sure it's wrong. yes, it's incorrect. did you identify your u and dv? show your steps so we see where you went wrong.
I set u=5x du=5 dv=cos(5x) and v=1/5 sin(5x) That gave me: I tried to use -1/5x cos(5x) for the part in the integral but it is still wrong.
Originally Posted by redman223 I set u=5x du=5 dv=cos(5x) and v=1/5 sin(5x) That gave me: I tried to use -1/5x cos(5x) for the part in the integral but it is still wrong. that is correct. all you need to do now is find and wrap it up
Thanks, for some reason I kept thinking that the derivative of 5x was 5x and not 5, lol. I came up with -1/5 cos(5x) and it was correct. Thanks.
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