Integration

**weezie23** · August 31st 2008, 07:51 AM

$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\intx^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?

**Moo** · August 31st 2008, 07:56 AM

Hello,

Originally Posted by weezie23

$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\int x^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?

Correct result

**o_O** · August 31st 2008, 07:59 AM

Originally Posted by weezie23

$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\int x^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?

Perfect. Now integrate each individual term.

**weezie23** · August 31st 2008, 08:08 AM

Originally Posted by o_O

Perfect. Now integrate each individual term.

$\frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c$

**Moo** · August 31st 2008, 08:10 AM

Originally Posted by weezie23

$\frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c$

Correct again

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