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Math Help - Integration

  1. #1
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    Integration

    \frac{x^3-7x^2+2}{x-4}

    So I start by divison \frac{x-4}{x^3/7x^2+2} to get \intx^2-3x-12-\frac{46}{x-4}dx Am I heading in the right direction?
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  2. #2
    Moo
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    Hello,
    Quote Originally Posted by weezie23 View Post
    \frac{x^3-7x^2+2}{x-4}

    So I start by divison \frac{x-4}{x^3/7x^2+2} to get \int x^2-3x-12-\frac{46}{x-4}dx Am I heading in the right direction?
    Correct result
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  3. #3
    o_O
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    Quote Originally Posted by weezie23 View Post
    \frac{x^3-7x^2+2}{x-4}

    So I start by divison \frac{x-4}{x^3/7x^2+2} to get \int x^2-3x-12-\frac{46}{x-4}dx Am I heading in the right direction?
    Perfect. Now integrate each individual term.
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  4. #4
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    Quote Originally Posted by o_O View Post
    Perfect. Now integrate each individual term.

    \frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c
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  5. #5
    Moo
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    Quote Originally Posted by weezie23 View Post
    \frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c
    Correct again
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