1. ## Integration

$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\intx^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?

2. Hello,
Originally Posted by weezie23
$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\int x^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?
Correct result

3. Originally Posted by weezie23
$\frac{x^3-7x^2+2}{x-4}$

So I start by divison $\frac{x-4}{x^3/7x^2+2}$ to get $\int x^2-3x-12-\frac{46}{x-4}dx$ Am I heading in the right direction?
Perfect. Now integrate each individual term.

4. Originally Posted by o_O
Perfect. Now integrate each individual term.

$\frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c$

5. Originally Posted by weezie23
$\frac {x^3}{3}-3\frac {x^2}{2}-12x-46*ln\mid x-4\mid +c$
Correct again