Originally Posted by
Chris L T521 The integrand is the same as saying the following:
$\displaystyle \frac{\sec(2x)}{\cos(2x)}=\sec(2x)\cdot\sec(2x)=\s ec^2(2x)$
Thus, you have the integral $\displaystyle \int\sec^2(2x)\,dx$
It should be a piece of cake from here.
I hope this helps.
--Chris