problem - integral x^3(sqrt(x^3+1)dx u = x^3 +1 du= 3x^2 du/3=x^2dx so integral u^1/2(du/3) = 1/3 integral u^1/2 du 1/3 (U^3/2)/(3/2) = 2/9 u^3/2 2/9(x^3+1)^3/2 + c
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Originally Posted by weezie23 problem - integral x^3(sqrt(x^3+1)dx u = x^3 +1 du= 3x^2 du/3=x^2dx so integral u^1/2(du/3) = 1/3 integral u^1/2 du 1/3 (U^3/2)/(3/2) = 2/9 u^3/2 2/9(x^3+1)^3/2 + c i suppose you meant $\displaystyle \int x^2 \sqrt{x^3 + 1}~dx$
yes - how do you post the equasions so clearly with the text?
Originally Posted by weezie23 yes well, in that case, you are correct. good job how do you post the equasions so clearly with the text? I used LaTeX
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