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Math Help - Area 3

  1. #1
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    Area 3

    Calculate the area by integration of the region limited by the curve:

    y=x+2, y=3x-3, y=1-x and 2y-3x+6=0


    And build the graph



    Answer:
    \frac{27}{4}
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  2. #2
    Super Member
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    y=x+2 y=3x-3
    x+2=3x-3
    P(\frac{5}{2},\frac{9}{2})

    x+2=1-x
    P(-\frac{1}{2},\frac{3}{2})

    2x+4=3x-6
    P(10,12)


    3x-3=1-x
    P(1,0)

    6x-6=3x-6
    P(0,-3)

    2-2x=3x-6
    P(\frac{7}{5},-\frac{2}{5}


    For graph. The integral of the -0,5 until 1 the (2x+1) + the integral of the 1 until 2,5 the (-2x+5). So I think the answer \frac{7}{2}
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