Find the gradient of the function 3sqrt theta^3 / 2 Sin 2 theta giving your answer as a product of factors.
I have looked at this equation and as far as can tell I need to use Chain rule, product rule and quotient rule.
Is this right? and if so in what order should i use them?
Sorry...I left it for you to try to simplify. Now that you're stuck, I'll now include the extra steps I left out.
Let's focus on the first grouped part in the numerator:
We see a something cancels out, and we can combine a couple terms:
Now when subtracted from the second term in the numerator, we get
The common factor to both terms is , but this is what we get when we pull it out:
Recall that the denominator of the derivative was
So we now see that
This is the same as saying
I think that the last one is even better...
Does this clarify things?
--Chris
Pleas excuse my ignorance, I followed everything you did and understood it, except for one part.
When you take the common factor of theta^-3/2 from both sides
You have sqrt(theta^3) I was told that that was the same as theta^3/2 not negative 3/2
Again i apologise if i'm being ignorant