The area under rcosθ =1 + tanθ, θ = -π/4 to θ = 0, is the same as the area under y=x(x-1), x = 0 to x=1.State true or false?Give reason? Learning is just like eating , it is not how much we eat it is how much we can digest.
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Originally Posted by puneet The area under rcosθ =1 + tanθ, θ = -π/4 to θ = 0, is the same as the area under y=x(x-1), x = 0 to x=1.State true or false?Give reason? Learning is just like eating , it is not how much we eat it is how much we can digest. see.. if we set and thus, how about the limits of integration? try to see if they give you same limits..
thanks
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