Originally Posted by kendon
you make the substitution , find , so the integral becomes:
.
Look OK to me.
Now:
which can be checked by differentiating it, you should get the integrand back.
RonL
Trying to integrate (arcsin(x))^2/(sqrt 1-x^2)
So far i have made
arcsin x = u and
du=1/(sqrt1-x^2).dx
I am at u^2 * du
I have spent hours on this and it appears obvious but i just don't get it! sorry
Any pointers i would be extremely grateful. I feel its something to do with the calculus relationship between the values of arcsin and du.
Thanks in advance
Ken