how do i do: $\int sqrt{x^2-1}\;dx$

2. Originally Posted by micheymichmich
how do i do: $\int sqrt{x^2-1}\;dx$
I suppose you mean $\int \sqrt{x^2 - 1}~dx$

we can use trigonometric substitution here. try $x = \sec \theta$

can you continue?

3. Originally Posted by Jhevon
I suppose you mean $\int \sqrt{x^2 - 1}~dx$

we can use trigonometric substitution here. try $x = \sec \theta$

can you continue?
yes. thank you