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Math Help - Integral 08

  1. #1
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    Integral 08

    \int e^(3cos2x) sen2xdx
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  2. #2
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    Hello,

    Let u=3cos2x. Then, du=-6sin2xdx.
    \int e^{3\cos 2x}\sin 2xdx<br />
=\int e^u\left(-\frac{1}{6}\right)du=-\frac{1}{6}e^u+C<br />
=-\frac{1}{6}e^{3\cos 2x}+C.
    ( C: integral constant)

    Bye.
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  3. #3
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    This is a very simply and obvious substitution, Apprientice123. This shouts clearly that you just have no desire to do any work. Come on. Step up your game.
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  4. #4
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    ok. thank you
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