# Math Help - Integral 08

1. ## Integral 08

$\int e^(3cos2x) sen2xdx$

2. Hello,

Let u=3cos2x. Then, du=-6sin2xdx.
$\int e^{3\cos 2x}\sin 2xdx
=\int e^u\left(-\frac{1}{6}\right)du=-\frac{1}{6}e^u+C
=-\frac{1}{6}e^{3\cos 2x}+C.$

( $C$: integral constant)

Bye.

3. This is a very simply and obvious substitution, Apprientice123. This shouts clearly that you just have no desire to do any work. Come on. Step up your game.

4. ok. thank you