Find the asymptote of
2r^2=tan2α
How to find it?
Hello, roshanhero!
Find the asymptotes of: .$\displaystyle 2r^2\:=\:\tan2\theta$
In polar coordinates, asymptotes occur where $\displaystyle r \to \infty$
We have: . $\displaystyle r^2 \;=\;\frac{1}{2}\tan2\theta$
We see that asymptotes occur where: $\displaystyle 2\theta \:=\:\frac{\pi}{2} + \pi n \quad\Rightarrow\quad \theta \:=\:\frac{\pi}{4} + \frac{\pi}{2}n$
I am terribly sorry,but I simply could not get it at all.I think I can easily find the horizontal,vertical and oblique asymptotes of the cartesian curve but I just don't have any concept regarding of finding asymptotes of the polar curve.Please explain it to me from the scratch.
What part of the discussion do you not understand? Do oyu know how to solve a trigometric equation such as $\displaystyle \cos (2 \theta) = 0$ ?
It may be that you're weak in the mathematical background assumed for these sorts of problems. In which case you're best advised to go back and revise the prerequisite mathematical concepts.