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Math Help - Help on differentiation

  1. #1
    Junior Member
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    Help on differentiation

    Q(x) = \frac{1}{\sqrt{2 \pi}} \int_x^\infty e^{- t^2/2} dt

    P = Q( \sqrt{2a \cdot u^2} ) \cdot e^{au^2}

    what is the answer if we differentiate P w.r.t. u^2 ???

    thanks
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by graticcio View Post
    Q(x) = \frac{1}{\sqrt{2 \pi}} \int_x^\infty e^{- t^2/2} dt

    P = Q( \sqrt{2a \cdot u^2} ) \cdot e^{au^2}

    what is the answer if we differentiate P w.r.t. u^2 ???

    thanks
    Put v=u^2, then:

    P(v)=Q( \sqrt{2a  v} )  ~e^{av}

     <br />
\frac{d}{dv}P(v)=\frac{\sqrt{2a}}{2\sqrt{v}}~Q'(\s  qrt{2a v} ) ~ e^{av}+aP(v)<br />

    RonL
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