Results 1 to 2 of 2

Math Help - Intergration

  1. #1
    Member
    Joined
    Jan 2008
    Posts
    132

    Intergration

    Find the area of the finite region enclosed between the following curves:
    y= 0.3x + 5 sin x and y = 2x

    Thank you for helping!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    o_O
    o_O is offline
    Primero Espada
    o_O's Avatar
    Joined
    Mar 2008
    From
    Canada
    Posts
    1,407
    It helps if you have a visual of what is going on. First we find the intersection points to determine the limits of integration:

    0.3x + 5\sin x = 2x \: \: \iff \: \: \sin x = 0.34 x

    This is impossible to solve algebraically so you're going have to obtain the intersection points via your graphing calculator. Let's call these intersection points x = a, 0, and b.

    If you graph it out, you'll see y = 2x is greater than 0.3x + 5sin x over the interval [a,0] and the other way around for the interval [0,b]. (Remember, area enclosed by two curves is given by the integral of the upper minus the lower function) So,

    A = \int_{a}^{0} \left[2x - \left(0.3x + 5\sin x\right)\right] dx + \int_{0}^{b} \left[(0.3x + 5\sin x) - 2x\right]dx
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Intergration
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 23rd 2011, 07:14 PM
  2. Intergration
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 9th 2008, 02:46 PM
  3. Intergration help!!!!!!
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 28th 2008, 07:41 AM
  4. help with intergration please
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 14th 2008, 07:10 PM
  5. Intergration
    Posted in the Calculus Forum
    Replies: 4
    Last Post: June 1st 2008, 07:17 PM

Search Tags


/mathhelpforum @mathhelpforum