1. ## Help needed!

I really need some help answering the following question. There is an example of how it should be completed but I don't understand it. The example has a diagram and advises the use of either Trapezium rule or Simpson's rule.

Question: Use a numerical method to find the area enclosed by the graph of y = x² sin x, the x axis and the lines x = 1 and x = 2.
Use an interval of 0.4

2. Originally Posted by norivea
I really need some help answering the following question. There is an example of how it should be completed but I don't understand it. The example has a diagram and advises the use of either Trapezium rule or Simpson's rule.

Question: Use a numerical method to find the area enclosed by the graph of y = x² sin x, the x axis and the lines x = 1 and x = 2.
Use an interval of 0.4

For example use 4 divisions.
Then,
$\Delta x=\frac{2-1}{4}=.25$
Thus, (by trapezoid rule),
$.5[f(1)+2f(1.25)+2f(1.5)+2f(1.75)+f(2)]\times .25$
You can do the calculations.

3. So just for further clarification, I have attached my answer to this post. The area is 4.5248 with n=10 by Trapezium Rule. When you increase the n, or decrease the interval h, the area will be approaching to the real value.
When n=100, the area is 4.5360
When n=1000, the area is 4.5361

Is this correct?

4. Originally Posted by norivea
So just for further clarification, I have attached my answer to this post. The area is 4.5248 with n=10 by Trapezium Rule. When you increase the n, or decrease the interval h, the area will be approaching to the real value.
When n=100, the area is 4.5360
When n=1000, the area is 4.5361

Is this correct?
What is K in your image file?

RonL

5. Hello, norivea,

Originally Posted by norivea
...
Question: Use a numerical method to find the area enclosed by the graph of y = x² sin x, the x axis and the lines x = 1 and x = 2.
Use an interval of 0.4...
the x-value shoul read 2.6 . Then the given interval make some sense.

I presume that the K in your image means "continueing"?

Greetings

EB