The sum ∑(from n = 1 to ∞) arctan [n/(n^4 - 2n^2 + 2)] is equal to:

A) (arctan 2 + arctan 3)/4

B) 4. (arctan 1)

C) -π/16

D) 3π/16

More than one options may be correct.

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- Aug 13th 2008, 07:57 AMfardeen_genThe sum of the trigonometric series...?
The sum ∑(from n = 1 to ∞) arctan [n/(n^4 - 2n^2 + 2)] is equal to:

A) (arctan 2 + arctan 3)/4

B) 4. (arctan 1)

C) -π/16

D) 3π/16

More than one options may be correct. - Aug 14th 2008, 10:13 AMfardeen_gen
To be more precise, it is http://alt1.artofproblemsolving.com/...7ebfe69b99.gif = ?

- Aug 14th 2008, 11:09 AMwingless
- Aug 15th 2008, 06:19 AMfardeen_gen
One of the answers is definitely true - this was what my instructor told me. Are you sure wingless that the the given sum is not equal to any of the options??