Find the surface area of the cone z=2sqrt(x^2+y^2) and above a region in the xy-plane with area 5.
If anyone could help me with this problem, I would really appreciate it.
Hello, John,Originally Posted by OntarioStud
as you may know the term describes the distance between the origin and a point in the xy-plane.
If you draw a plane cut through the cone along the z-axis it'll look like the diagram which I attached.
With your cone you get: .
The slope s is .
The surface area of a cone contains the base circle and the area, which is produced by the sloping line:
Notice: I've corrected my mistake. I'm sorry if the previous result caused any irritation.
This surface has the value 5. So you get: . Solve for r and re-substitute. You'll get the equation: