# Multiple Integration Volume

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• Jul 30th 2006, 07:52 PM
JaysFan31
Multiple Integration Volume
Any help greatly appreciated.

Find the volume of the solid under the surface z=(8+x)(8+y) and above the region in the xy-plane given by (x^2)+(y^2) less than or equal to 36.
Hint: Use polar coordinates.

Thanks in advance.

Mike
• Jul 30th 2006, 10:05 PM
CaptainBlack
Quote:

Originally Posted by JaysFan31
Any help greatly appreciated.

Find the volume of the solid under the surface z=(8+x)(8+y) and above the region in the xy-plane given by (x^2)+(y^2) less than or equal to 36.
Hint: Use polar coordinates.

Thanks in advance.

Mike

In cylindrical polars we have:

$
I=\int_{r=0}^6 \int_{\theta=0}^{2\pi} \int_{z=0}^{(8+r \cos(\theta))(8+r\sin(\theta)} 1\ dz\ d\theta\ r.dr$
$=\int_{r=0}^6 \int_{\theta=0}^{2\pi} \int_{z=0}^{(8+r \cos(\theta))(8+r\sin(\theta)} r\ dz\ d\theta\ dr
$

Where we have used the fact that the volume element in cylindrical polars
is $r\ d\theta\ dr \ dz$, and changed the order of integration to suit the problem.

RonL