Find the area of the region between y = x^2 and y = 4-3x from x = -1 to x = 4/3

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- Aug 10th 2008, 08:45 PMMathGeek06Area of the Region Between Two Curves
Find the area of the region between y = x^2 and y = 4-3x from x = -1 to x = 4/3

- Aug 10th 2008, 08:52 PMChris L T521
Did you graph the bounded region? This will help you set up the integral.

http://img.photobucket.com/albums/v4...tuff/parab.jpg

Recall that the area between two curves is

I hope this helps!

--Chris - Aug 10th 2008, 09:00 PMMathGeek06
Yes, I graphed the bounded region but when I set up my integrals, I got a negative answer, which clearly was incorrect.

I had an integral of ((4-3x) - x^3)) from x = -1 to x= 1 + the integral ((x^2) - (4-3x)) from x = 1 to x = 4/3. - Aug 10th 2008, 09:24 PMChris L T521