P.S. #2 is just . WHY?
Hello!
I've been having trouble solving these 2 trig limits, any help would be appreciated.
find the limit as x -> 0
1) sin7x / sin4x
2) [sin (cos x)] / sec x
I need to re-arrange both these equations so that 0 can be subbed into x and not get 0 /0. For 1) i multiplied the equation by 7x over 7x and re-arranged it to (sin7x) / 7x * (7x) / sin4x. The sin7x / 7x becomes 1 because of the trig limit properties, but what do I do with 7x / sin4x?
I don't even know how to start 2
For those of you that don't know the 2 trig limit properties of the top of your head, here they are:
limit as x -> 0 of sin x / x = 1
limit as x -> 0 of cos x - 1 / x = 0
Thanks for any help
-Jackson