Hi

I'm sitting a quiz for maths and i'm having trouble with this question...

If anyone could help I would be very much appreciated!

So the question asks to...

Find the equation of the plane containing the line

x = (0, 0, 1) + t (0, -1, 0) and the point (1, 1, 0).

Here is my attempt:

This line passes through the pt P(0, 0, 1)

So we need a second vector which spans the plane together with the direction vector of the line.

If Q(1, 1, 0) then the second vector is:

PQ = (1, 1, 0) - (0, 0, 1) = (1, 1, -1)

So the equation of the plane is:

r = (0, 0, 1) + t (0,-1, 0) + s (1, 1, -1)

But I can't seem to get my head around which answer this comes to...

A. z - x = 1

B. z + x = 1

C. z - x = - 1

D. z + x = - 1