Can't solve these two. Apparently you're NOT supposed to use a trig substitution for the second one. I don't know how you can for the first since 5 isn't a prime number.
First one:
∫ dx/[x*√(5-x^2)]
Second one:
∫ x^3*√(9-x^2) dx
Thanks
Can't solve these two. Apparently you're NOT supposed to use a trig substitution for the second one. I don't know how you can for the first since 5 isn't a prime number.
First one:
∫ dx/[x*√(5-x^2)]
Second one:
∫ x^3*√(9-x^2) dx
Thanks