Hi everyone.
I'm having a smole problem with this function H(x)=(2+|x|)/(1-|x|) . So my function has 4 equalities :
H(x)=(2+x)/(1-x) for x>0,
H(x)=(2+x)/(1+x) for x>0,
H(x)=(2-x)/(1-x) for x<0,
H(x)=(2-x)/(1+x) for x<0.
I need to find lim x->1+ H(x) - so 1 from right side.
Shall i look on H(x)=(2+x)/(1-x) or maybe H(x)=(2-x)/(1-x) ???? for both of them lim is -infinity.
Also lim x-> -1 H(x)
and again H(x)=(2+x)/(1+x) or maybe H(x)=(2-x)/(1+x) . For the first one lim is 3/2 for the second one lim is 1/2.
Also lim -> infinity H(x)
and lim ->0 H(x)
I'll be thankful for any help!