Hi everyone.

I'm having a smole problem with this function H(x)=(2+|x|)/(1-|x|) . So my function has 4 equalities :

H(x)=(2+x)/(1-x) for x>0,

H(x)=(2+x)/(1+x) for x>0,

H(x)=(2-x)/(1-x) for x<0,

H(x)=(2-x)/(1+x) for x<0.

I need to find lim x->1+ H(x) - so 1 from right side.

Shall i look on H(x)=(2+x)/(1-x) or maybe H(x)=(2-x)/(1-x) ???? for both of them lim is -infinity.

Also lim x-> -1 H(x)

and again H(x)=(2+x)/(1+x) or maybe H(x)=(2-x)/(1+x) . For the first one lim is 3/2 for the second one lim is 1/2.

Also lim -> infinity H(x)

and lim ->0 H(x)

I'll be thankful for any help!