This one is actually very easy.
Let
Hi,
I'm having real trouble with the following integration. I've tried it by parts but that's not going well for me.
The given answer I have is but I unfortunately can't seem to arrive at it (or any other answer.)
Can anyone help? Thanks!
Ah-ah! I knew I was missing something! Thanks.
However, there's something I'm unclear about here. Using galactus's suggestion of letting , we get , and so
That's fine, until I attempt JaneBennet's alternative suggestion: let , so , and so
But I think and aren't equivalent, are they? What have I done wrong there? (Or is it that both are correct but the constants would have different values?)
Hello, Wonkihead!
You left out the "plus C" . . .
There's something I'm unclear about here.
Using galactus' suggestion of letting , we get
. . and so: .
That's fine, until I attempt JaneBennet's alternative suggestion:
let , so ,
. . and so: .
But I think and aren't equivalent, are they? . . . . Yes, they are
What have I done wrong there?
Recall the Identity: .
You should have had: .
If these are equivalent: .
Multiply by 2: .
If that constant is 1, we have the Identity.
. .The expressions are equivalent!
Edit: flyingsquirrel beat me to me . . . *sigh*
.