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Math Help - Need help with taking derivative + simplying a function

  1. #1
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    Need help with taking derivative + simplying a function

    y = (2x-3)^2 / (x^3 - 7)^3

    I used the quotient + chain rule to expand it out and got:

    [(4(x^3)^3 (2x-3)) - ((9x^2)(2x-3)^2 (x^3 -7)^2)] / (x^3 - 7)^6

    I *think* thats right, but if anyone wants to check it, I'd appreciate it. However, I'm having trouble simplifying from there. I think I can take out a common factor of (2x-3)(x^3 -7)^2 ? If so, what can I do from there? If not, what do I do?

    Sorry if the equations looks messy I haven't learned how to use that code to make it look good yet.

    Thanks in advance for any help.
    -Jackson
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  2. #2
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    Quote Originally Posted by TheJacksonater View Post
    y = (2x-3)^2 / (x^3 - 7)^3

    I used the quotient + chain rule to expand it out and got:

    [(4(x^3-7)^3 (2x-3)) - ((9x^2)(2x-3)^2 (x^3 -7)^2)] / (x^3 - 7)^6

    I *think* thats right (unfortunately no. See correction in red), but if anyone wants to check it, I'd appreciate it. However, I'm having trouble simplifying from there. I think I can take out a common factor of (2x-3)(x^3 -7)^2 ? If so, what can I do from there? If not, what do I do?

    Sorry if the equations looks messy I haven't learned how to use that code to make it look good yet.

    Thanks in advance for any help.
    -Jackson
    Factor out (x^3-7)^2 in the numerator and split the denominator into (x^3-7)^2 * (x^3-7)^4 and then cancel the common factor.
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