Originally Posted by

**omniconsum3r** ...

1. Show that every (degree 3) polynomial has exactly one point where its second derivative is zero. Call this point P.

2. The show if a polynomial has three x-intercepts x1, x2, and x3, then x-coordinate of P is equal to **(**x1+x2+x3**)**/3.

Any help would be greatly appreciated. I am taking calculus after 10 years so I am having a bit of difficulty, but I am learning and picking it up again. I didn't know where else to go. Thank you for your time. Thank you, thank you, thank you, thank you..lol